The points (0, 27) and (-9, 0) are on the line
The equation of the line is given that
3y - 9x = 81
The coordinates of the first point = (0, 27)
Substitute the value of x and y in the equation
3(27) - 9(0) = 81
Multiply the terms
81 - 0 = 81
Add the terms
81 = 81
The point (0, 27) is on the line
The coordinates of the second point = (-9, 0)
Substitute the value of the x and y in the equation
3(0) - 9(-9) = 81
Multiply the terms
0 + 81 = 81
Add the terms
81 = 81
The point (-9, 0) is on the lines
Hence, the points (0, 27) and (-9, 0) are on the line
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