The system of equations that would be used to find the number of boxes of printer paper, represented by p, and the number of printer ribbons, represented by R, that Denny plans to purchase is 11.99p+5.95R = 65.72 and 12.25p+5.80R = 65.75.
According to the question,
We have the following information:
At ACE computers ,a box of paper cost $11. 99 each while printer ribbons cost $5. 95 each. This would result in a total cost of $65. 72. At better computer, a box of paper cost $12. 25 each while printer ribbons cost $5.80 each. This will result in total cost of $65. 75.
Now, the number of boxes of print paper is p and the number of printer ribbons is R.
So, we have the following equations for each case respectively:
11.99p+5.95R = 65.72
12.25p+5.80R = 65.75
Hence, the system of equations that would be used to find the number of boxes of printer paper, represented by p, and the number of printer ribbons, represented by R, that Denny plans to purchase is 11.99p+5.95R = 65.72 and 12.25p+5.80R = 65.75.
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