(a) Using combination, the number of ways to choose 10 players to take the field is 286. (b) Using permutation, the number of ways to assign the 10 positions is 1037836800.
The softball team has 13 people for a game.
a) Since the sequence doesn't matter, there are a total of 13 ways to select 10 players, which results in the following combination:
₁₃C₁₀ = 13! / ( 13 - 10 )! 10!
₁₃C₁₀ = ( 13 × 12 × 11 ) / ( 3 × 2 )
₁₃C₁₀ = 13 × 2 × 11
₁₃C₁₀ = 286
b) The permutation of 13 players for 10 slots yields a total of possible positions that can be assigned by choosing 10 players:
₁₃P₁₀ = 13! / ( 13! - 10! )
₁₃P₁₀ = 13! / 3!
₁₃P₁₀ = 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4
₁₃P₁₀ = 1037836800
Learn more about of permutation here
https://brainly.com/question/29217044
#SPJ4
