two sets are formed using 100 elements. there are 67 elements in one set and 72 in the other. how many elements are in the intersection of the two sets?

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favorable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.

Probability(Event) = Favorable Outcomes/Total Outcomes = x/n

Union: -

If set A and set B are two sets, then A union B is the set that contains all the elements of set A and set B. It is denoted as A ∪ B.

Example: Set A = {1,2,3} and B = {4,5,6}, then A union B is:

A ∪ B = {1,2,3,4,5,6}

Intersection:-

If set A and set B are two sets, then A intersection B is the set that contains only the common elements between set A and set B. It is denoted as A ∩ B.

Example: Set A = {1,2,3} and B = {4,5,6}, then A intersection B is:

A ∩ B = { } or Ø

Since A and B do not have any elements in common, so their intersection will give null set.

P(AUB) = P(A) + P(B) - P(A∩B)

Here, P (A) = the number of elements in the set A and so on.

We know that:

P (A)= 67

P (B)= 72

and P (AUB) = 100

So, we can solve for the number in the intersection i.e. P(A∩B) = P(A) + P(B) - P(AUB)

P(A∩B) = 67 + 72 - 100

P(A∩B) = 139 - 100

P(A∩B) = 39.

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