The Ka value for the monoprotic acid on dissociation is found to be 16.44.
The dissociation of monoprotic acid HA is as,
HA = H⁺ + A⁻
So, the Ka value is defined as,
Ka = [H⁺][A⁻]/[HA]
The pH of a compound is given as,
log([H⁺]) = pH
The given pH is 2.8, so,
log([H⁺]) = 2.8
[H⁺] = 16.44 M.
Now, as we can see from the equation,
[H⁺] = [A⁻] = [HA]
So, putting the values for Ka,
Ka = [H⁺][A⁻]/[HA]
Ka = 16.44×16.44/16.44
Ka= 16.44
So, the value of Ka for this acid is 16.44.
To know more about pH value of the solution, visit,
https://brainly.com/question/172153
#SPJ4
