Claudia contains five 10-cent pieces.
Let Claudia, have 'x' 5-cent coins and (12 - x) 10-cent coins.
It is easily observed that any multiple of 5 between 5 and 5x + 10(12 - x)
= 120 - 5x it can be obtained by a combination of coins.
Thus, 24 - x = 17 combinations can be made, so x = 7.
But the answer is not 7, because we are asked for the number of 10-cent coins, which is 12 - 7 = 5
Therefore, Claudia has 5 10-cent coins.
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