The perimeter of triangle ABC is 3 cm.
Given:- AB is congruent to segment AC
AB= AC= 1/2x + 1/4
BC= 5/2-x
Perimeter of a triangle = Sum of all sides
= (1/2x + 1/4) + (1/2x + 1/4) + (5/2-x)
= 1/2x +1/2x -x +1/4+1/4+5/2
= 3 cm
Therefore, the perimeter of triangle ABC is 3 cm.
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