The sum of the digits of the integers that was erased was 403.
Consider the 1st digit be x and last be 'x + 5'.
Let the sum of all five integers is 'a'.
So,
5x + a = 2012
5x = 2012 - a
And 2012 must be divisible by 5
So if a = 12 we have x + (x + 1) + ( x + 2) + (x + 4)+ (x + 5)
5x + 12 = 2012
See that x + 3 was erased
5x = 2012 -12
5x = 2000
x = 400
And,
x + 3 = 400 + 3
Sum = 403 was erased.
Thus, the sum of the digits of the integers that was erased was 403.
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