a certain planet has equatorial radius about 0.542 times that of the earth, and mass only 0.110 times that of the earth. calculate the free-fall acceleration due to gravity on this planet in units of gg (earth's gravitational acceleration).

Respuesta :

The value of the free-fall acceleration due to gravity on this planet in unit of g is 0.37g

The acceleration due to gravity of a planet is given by the relation,

g = GM/R²

g is acceleration due to gravity(which is 9.8m/s² on earth),

G is the universal gravitational constant,

R is rhe radius of the planet,

M is the mass of the planet.

Now, for this planet, the mass of 0.110 times of earth and the radius is 0.542 times of the earth.

So, putting values for this planet in the formula above to find g',

g' = G(0.110M)/(0.542R)²

g' = (0.110/(0.542)²)GM/R²

g' = 0.37g

So, the value of acceleration due to gravity on this planet is 0.37g m/s².

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