an 8 kg crate is pulled 5m up a 30 degree incline by a rope angled 18 degree above the incline. the tension in the rope is 120n and the crates coefficient of friction on the incline is .25. a) how much work is done by the tension, gravity, and the normal force? b) what is the increase in thermal energy of the crate and incline?

Respuesta :

The work done by the tension is 593.4 Joules, the work done by the gravity is -179 Joules, the work done by the normal force is 0 Joules and the increase in the thermal energy of the create and incline is 25.7 Joules.

The mass of the crate is 8 kg and it is being pulled up 5m on 30 degree inclined plane by a rope inclined at an angle 18 degree above the incline itself.

The tension in the Rope is 120 Newton and the coefficient of friction between the crate and the incline is 0.25.

The angle made by the tension T with respect to the horizontal ground will be 30 degree + 18 degrees.

So, the angle made by Tension is 48°.

There will also be a normal force N on the crate.

(a) Solving for work done,

So, work done by tension,

W = Tcos48°(5)

W = 593.4J

Work done by gravity, W',

W' = Mgsin30°(5)

W' = -179J

Work done by gravity will be negative because the direction of the force applied and the displacement of the crate is opposite.

There will be no work done by the normal force because the force applied by the normal force is perpendicular to the direction of the motion of the crate.

(b) the increase in the thermal energy of the create and inclined will be equal to the work done by the friction,

Work done by friction = un(5)

Work done by friction = (uMgcos30°-Tsin18°)(5)

Work done by friction = 25.76J.

So, the increase in the thermal energy is 25.76 Joules.

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