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consider a neutron star with a mass equal to the sun, a radius of 11 km , and a rotation period of 1.0 s . what is the speed of a point on the equator of the star?express your answer with the appropriate units.

Respuesta :

At equator line the speed of the star is 69115 m/s

When a big star runs out of heat and collapses, neutron stars are created. Every proton and electron in the star's core, or most central region, fuse into neutrons as it falls. These freshly generated neutrons can stop the collapse, leaving a neutron star behind, if the core of the collapsing star is between one and three solar masses.

Radius is 11 km

Period of rotation is 1 second

Converting radius to meters:

11 km = 11 x 10^3 = 11000m

We know that the velocity relation is v = 2πr/T

v = 2 x π x r / 1

v = 2π x 11000

v = 69115 m/s

Hence the speed of the star at the equator is 69115 m/s

Learn more about neutron star at

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