Respuesta :
The absolute value of the difference between the first and second numbers is 5.
Here we have to find the difference between the first and the second numbers.
There are three statements.
Let a, b, and c be the first, second, and third numbers respectively.
The first statement is that the sum of the three number is 96.
The second statement is that the first number is 6 times the third number.
a = 6c
The third statement is that the third number is 40 less than the second number.
c = b - 40
b = c + 40
The sum of the three numbers is 96.
a + b + c = 96
6c + c + 40 + c = 96
8c = 96 - 40
8c = 56
c = 7
As a = 6c and b = c + 40
Now put the value of c as 7 we have:
a = 6 × 7
= 42
b = 7 + 40
= 47
Difference between the first and second numbers= 47 - 42
= 5
Therefore the difference is 5.
To know more about the number refer to the link given below:
https://brainly.com/question/21289653
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