If rp is 0.27ra, then a moon's orbital eccentricity is 0.57. Thus, option (a) is the correct answer.
Though the moon does not move around andra in a perfect ellipse, here, we assume that the moon's orbit is in the shape of an ellipse, we know that:
[tex]e = \frac{ra - rp}{ra + rp}[/tex] ... (i)
where e ⇒ eccentricity of the ellipse
ra ⇒ apoapsis i.e., the longest distance between the moon and its planet
rp ⇒ periapsis i.e., the shortest distance between the moon and its planet
From the question, we know
rp = 0.27 ra
Putting this value in equation (i) we get:
[tex]e = \frac{ra-0.27ra}{ra+0.27ra}\\[/tex]
[tex]e=\frac{0.73ra}{1.27ra}[/tex]
e = 0.57
Hence, if rp is 0.27 of ra, the moon's orbital eccentricity is 0.57.
To know more about eccentricity, click:
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