The boxes filled by the machine are underweight if the standard deviation is 0. 3 oz is 0.62%
we are given a box of oatmean containing 16 oz, a machine that fille the oatmeal boxes on an average of 16.5 oz boxes and the boxes filled by the machine have weights that can be closely approximated by a normal curve, at last, we are given the standard deviation of 0. 3 oz .The formula we are referring to for calculating the z score is
z = x- mean /standard deviation , where x is the observed value
So for the standard value of 0.3 oz, z= 16-16.5/0.3 = -2.5
The probability for the score -2.5 is s 0.0062 or 0.62%
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