Respuesta :
The probability of randomly selecting a red, then a free marble from a bag of 5 red, 8 green, and 3 marbles
a) 0.1563
b) 0.1667
Since we are given with bag of 5 red, 8 green, and 3 marbles. so, r=5, g=8 and b= 3. For the first case, we replace the first marble before drawing the second, the total number of marble = 5 + 8 + 3 = 16. So, the probability of drawing a red marble at the 1st attempt is: 5/16. Then, the first marble is replaced back into the bag before making the second draw. Probability of drawing green marbles at the second draw is: 8/16= 1/2, Therefore the probability of selecting a red, then a green marble is: 5/16 * 1/2 = 5/32 =0.1563
For the second case , we do not replace the first marble, the probability of drawing a red marble at the 1st draw is:5/16 . Since we don't replace the balls so the number of marbles remaining in the bag is: 16-1 =15 ,the probability of drawing green marbles at the second draw is: 8/15, therefore the combined probability of selecting a red, then a green marble is: 5/16 * 8/15 =0.1667
To know more about probability refer to the link https://brainly.com/question/11234923?referrer=searchResults.
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