Mass of potassium bromide must be dissolved to prepare 100 ml of a 0.164 m aqueous solution is 1.95 gram
It is given that
volume of aqueous solution = 100 ml
molarity of solution = 0.164 m
We have to find mass of potassium bromide
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution
Molarity = (given mass/molar mass) x (1/volume of solution)
0.164 = (mass/119) x 1000/100
0.164 = mass/119 x 10
0.164 x 119/10 = mass
mass = 1.95 gram
Hence, Mass of potassium bromide must be dissolved to prepare 100 ml of a 0.164 m aqueous solution is 1.95 gram
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