Mass of CH3OH must be added to water to prepare 250 ml of a solution is
24.03 gram
It is given that
volume of solution = 250 ml
molarity of solution = 3.0 M
We have to find Mass of CH3OH
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution
Molarity = (given mass/molar mass) x (1/volume)
3 m = (given mass/32.04) x 1000/250
3 = given mass/32.04 x 4
(3 x 32.04)/4 = given mass
given mass = 24.03 gram
Hence, Mass of CH3OH must be added to water to prepare 250 ml of a solution is 24.03 gram
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