3. The volume of the new gumball machine is of 861.75 in³.
4. This is a real solution, as it is a positive number.
The volume of the old machine was of:
5575 in.³
(as stated in the problem)
The volume of the new machine is obtained as follows:
532 in.³ less than 1/4 of the volume of the globe of the giant gumball machine.
One fourth of the volume of the old machine is obtained as follows:
1/4 x 5575 in³ = 1393.75 in³.
532 in.³ less than that is obtained as follows:
1393.75 - 532 = 861.75 in³.
An extraneous volume is a negative value to the volume, as the volume cannot be negative. Since the number is positive, it represents a real solution.
More can be learned about volumes at https://brainly.com/question/463363
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