RTT0+ RTT1+RTT2+ RTT3+ 2*RTTHTTP= 2 + 45 + 41 + 2 + 2*35 = 160 msecs is the amount of time it takes from the time the browser makes the web request to the time the page is shown in the browser.
Please take note that two RTTHTTP requests are required to fetch the HTML object: one RTTHTTP is required to create the TCP connection, and a second RTTHTTP is required to do the HTTP GET/response over that TCP connection. Let's say you click a link in your web browser to access a website.
A DNS query is required in order to get the IP address because it is not cached in your local host for the associated URL. Assume that before your host receives an IP address from DNS, two DNS servers are consulted. The local DNS cache is the first DNS server to be contacted, with an RTT delay of RTT0 = 2 msecs. The RTT for the second DNS server contacted is 21 milliseconds.
Let's start by assuming that the link-related Web page just has one object, which is a brief section of HTML text. Assume that the RTT is RTTHTTP = 10 msecs between the local host and the Web server hosting the object.
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