Question

Phenyl magnesium bromide is used as a Grignard reagent in organic synthesis. Determine its empirical and molecular formula if it’s molar mass is 181. 313 g/mol and it contains 39. 7458 % C, 2. 77956 % H, 13. 4050 % Mg, and 44. 0697 % Br

Answer 1

Phenyl magnesium bromide ($PhMgBr$) is an organomagnesium reagent specially utilized in Grignard reaction, which unearths utility as the important thing step within side the synthesis of (S)-2(diphenyl methyl) pyrrolidine, a chiral solvating agent for the NMR analysis.

All possibilities should upload as much as a 100– can discover the lacking percent of Br. a 100-55.93036 = 44.06964% Br.

• Assume a 100 g of sample → 39.7458 g C, 2.77956 g H, 13.4050 g Mg, 44.06964 g Br Convert grams to moles.  39.7458 g C / 12 g/mol = 3.309392173 mol C2.77956 g H / 1 g/mol = 2.77956 mol H13.4050 g Mg / 24.31 g/mol = 0.5514191691 mol Mg 44.06964 g Br / 79.9 g/mol = 0.5515599499 mol Br divide via through the bottom variety of moles. C = 6H = 5 Mg = 1 Br = 1.
• Empirical formulation = $C_{6} H_{5} MgBr$.
• To discover the molecular formulation, first calculate the molar mass of the empirical formulation. 181.27 g/mol divide the molar mass of the molecular formulation through the empirical formulation to calculate the issue you should multiply the empirical formulation through. In this case, 181.313/181.27 = 1, so the molecular formulation = $C_{6} H_{5} MgBr$.

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