An object 4.0 cm in height and mirror with a focal length of 10.0 cm .The position of its image in relation to the mirror 40.0 cm in front of the mirror, the characteristics of the image is real, upright, 5.0 times bigger.
H=4 cm
u=8 cm
f=10 cm
using mirror formula
1/f=1/u+1/v
1/v=1/f-1/u
v=-80/2
v=-40 cm -ve sign is show image infront of mirror
magnification is m=-v/u
m=+40/8
m=5
The inverse of the optical power of an optical system, the focal length provides a measurement of how strongly the system converges or diverges light. A system's light converges when the focal length is positive, while it diverges when the focal length is negative.
Learn more about focal length here:
https://brainly.com/question/16188698
#SPJ4