The resulting 50 g ball of clay moves with a speed and direction of 1.7 m/s. As a result, the ultimate velocity of the two ball's weight after contact is 1.7 m/s and their direction is 450.
the first clay ball's weight, m1, is 20 g (0.02 kg), and its starting velocity, u1, is 3 m/s; the second ball's weight, m2, is 30 g (0.03 kg), and its beginning velocity, u2, is 2 m/s.
The fist ball's starting momentum is determined using the formulas below;
P1 equals (m1u1), (0.02)(3), (0.06)kg/s, and P1 (m1u1).
To calculate the two balls' final velocity, use the momentum conservation principle;
mv=0.085 v=0.085/0.05 v=1.7 m/s
The direction of the two ball's velocity is calculated as follows;
tetha = tan^-1 (0.06/0.06)
=45 degrees
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