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water from a fire hose is directed horizontally against a wall at a rate of 47.9 kg/s and a speed of 28.6 m/s. calculate the magnitude of the force exerted on the wall, assuming the water comes to a complete stop when hitting the car, with no splash-back.

Respuesta :

The magnitude of the force exerted on the wall is 2100N.

Based on the intersection of an object's mass and velocity, momentum quantifies the "motion content" of the object. For instance, when velocity doubles, momentum also doubles. Similarly to this, if two objects are moving at the same speed, the one with the larger mass also has the larger momentum.

On the other hand, force is the push or pull that is used to change an object's momentum. According to Newton's Second Law of Motion, force is calculated by multiplying the mass by acceleration. Since acceleration is the change in velocity divided by time, the following relationship can be used to link the two ideas:

force = mass x (velocity / time) = (mass x velocity) / time = momentum / time

Multiplying both sides of this equation by time:

force x time = momentum

So according to the Question,

In 1 sec 50kg water with 42m/s

speed falls horizontally on the wall and loses its speed to zero.

So initial momentum of 50kg of water

=50×42kgm/s

And the final momentum is zero

So force =

change in momentum/Time=

50×42/1

=2100N

Based on the intersection of an object's mass and velocity, momentum quantifies the "motion content" of the object. For instance, when velocity doubles, momentum also doubles. Similarly to this, if two objects are moving at the same speed, the one with the larger mass also has the larger momentum.

On the other hand, force is the push or pull that is used to change an object's momentum. According to Newton's Second Law of Motion, force is calculated by multiplying the mass by acceleration. Since acceleration is the change in velocity divided by time, the following relationship can be used to link the two ideas:

force = mass x (velocity / time) = (mass x velocity) / time = momentum / time

Multiplying both sides of this equation by time:

force x time = momentum

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