what pressure would it take to compress 350. l of helium gas initially at 1.00 atm into a 2.00 l tank at constant temperature?

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Neetoo

1.75 atm pressure it takes to compress 350 L of helium gas initially at 1.00 atm into a 2.00 L tank at a constant temperature.

Initial volume of helium gas (V1) = 350 L

Final volume of helium gas (V2) = 2.00 L

Initial pressure of helium gas (P1) = 1.00 atm

Final pressure of helium gas (P2) = ? atm

To find out the final pressure (P2) we will use the following equation

    P1V1 = P2V2

Rearrange the equation for final pressure (P2)

  P2 = P1V1 / V2

Put the values in the above equation

   P2 = 1.00 atm × 350 L / 2.00 L

   P2 = 350 atm / 2.00

   P2 = 1.75 atm

You can also learn about constant temperature from the following question:

https://brainly.com/question/12152879

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