a 2250 kg elevator moves with a downward acceleration of 1.5 m/s2 . what is the tension in the cable that supports the elevator?

Respuesta :

The tension in the cable that supports the elevator is 19,125 Newton's.

The formula to be used for calculation is -

T = m(g - a), where T refers to tension, m is mass, g is acceleration due to gravity and a is acceleration. Taking value of g as 10 m/s². Keep the values to find the tension in the cable -

T = 2250 (10 - 1.5)

Performing subtraction on Right Hand Side of the equation

T = 2250 × 8.5

Performing multiplication on Right Hand Side of the equation

T = 19,125 N

Hence, the tension is 19,125 Newton's.

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