Question

Suppose that a recent poll of american households about pet ownership found that for households with pets, 45% owned a dog, 34% owned a cat, and 10% owned a bird. Suppose that three households are selected randomly and with replacement and the ownership is mutually exclusive. 25) what is the probability that all three randomly selected households own a dog? (round to the nearest hundredth)

Answer 1

There is a 0.091125 probability that all three randomly chosen houses have dogs.

In light of this, imagine that a recent survey of American homes regarding pet ownership revealed that 45% of households with pets were dog-owning, 34% were cat-owning, and 10% were bird-owning households.

• Three families are chosen at random, replaced, and with mutually exclusive ownership.

The calculation of probability is as follows based on the facts above:

=0.43^3

= 0.091125

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