The standard entropy change for the combustion of 1 mole of diamond at room temperature is 6.22 J / K mol.
The reaction is given as :
C (diamond) + O₂ -----> CO₂
At room temperature the value of S° is given as follows :
C = 2.38 J / K mol
O₂ = 205.2 J/Kmol
CO₂ = 213.8 J/Kmol
The standard entropy change is given as :
ΔS° = ∑S° product - ∑ S° reactant
ΔS° = ( 213.8 ) - ( 2.38 + 205.2)
ΔS° = 213.8 - 207.58
ΔS° = 6.22 J / K mol
Thus, The standard entropy change for the combustion of 1 mole of diamond at room temperature is 6.22 J / K mol.
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