A 44.9-g sample of Ne gas exerts a certain pressure in a container of fixed volume. The mass of Ar is required to exert half the pressure at the same conditions of volume and temperature is 44.6 g.
given that :
mass of Ne = 44.9 g
moles of Ne = mass / molar mass
= 44.9 / 20
= 2.24 mol
using ideal gas equation we get :
P V = n RT
where,
volume V = constant
R = constant
T = temperature
therefore :
P1 / n1 = P2 / n2
P2 = P1 / 2
P1 / n1 = (P1 / 2 ) / n2
n2 = 2.24 / 2
= 1.12 mol
Mass of Ar = moles × molar mass
= 1.12 × 39.9
= 44.6 g.
Thus, A 44.9-g sample of Ne gas exerts a certain pressure in a container of fixed volume. The mass of Ar is required to exert half the pressure at the same conditions of volume and temperature is 44.6 g.
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