Question

: a 3.0 cm tall object is 15 cm in front of concave (convex) mirror with focal length of 25 cm. (a) draw a qualitatively accurate ray diagram showing image formation. indicate the principal axis and the focal points . (b) is the image be real or virtual? is the image inverted or upright ? (c) where is the image located? (d) what is the magnification and the height of the image?

Answer 1

1. Ray diagram (in image )
2. Nature of image is real and inverted.
3. Image location is 5cm.
4. Magnification and height of image is 0.2 and 2.8cm respectively.

Ray diagram is inscribed in image.

Sign convention of the image decides the nature of image . And as per the question the image formed will be real.

As the foci of all points meets at one point and diverge , so the nature of image is inverted.

Image located below the principal axis and thereby will diminish as the object distance increases.

Image will be located at 5cm away from radius of curvature.

Magnification refers to ratio of image and object sizes and related to negative of distances of image and object from center of curvature.

Mathematics:-

$\\\\magnification = \frac{x}{y}$

therefore m= 3/15=1/5=0.2

since magnification refers to ratio so its unitless.

Hence total height of image = 3-0.2 = 2.8cm

To learn more about Magnification -

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