The correct answer is 22.66 rad/s².
Judging by the data delivered corresponding to the change of speeds and the number of revolutions, it is possible to complement the question by deducing that the angular acceleration is sought. Then to solve this problem we will apply the kinematic equations of angular motion, for which the square of the velocity change is described, in proportion to twice the product between the angular acceleration and the angle. That is to say,
([tex]\omega_{f}[/tex])² - ([tex]\omega_{i}[/tex])² = 2αθ
Where,
[tex]\omega_{f}[/tex] = Final angular velocity
[tex]\omega_{i}[/tex] = Initial angular velocity
α= Angular acceleration
θ = Angular displacement
Now convert the revolutions in radians we have,
θ = 2.6 rev [tex](\frac{2\pi rad}{1 rev})[/tex]
θ = 16.33 rad
Replacing and solving to find angular acceleration we have
[tex](\omega_{f})^{2}[/tex] - [tex](\omega_{i})^{2}[/tex] = 2αθ
α = [tex](\omega_{f})^{2}[/tex] - [tex](\omega_{i})^{2}[/tex] / 2θ
α = {(29.9)² - (12.4)²} / 2 * 16.33
α or angular acceleration = 22.66 rad/s²
Therefore the angular acceleration of the propeller is 22.66 rad/s².
To learn more about angular acceleration, refer: https://brainly.com/question/1592013
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