Question

during 1996,1996, the population of sudbury decreased by 6\%6% while the population of victoria increased by 14\%. at the end of the 1996,1996, the populations of these cities were equal. what was the ratio of the population of sudbury to the population of victoria at the beginning of 19961996?

Answer 1

For the given data of population of two cities Sudbury and Victoria , the ratio of the population of the two cities in the beginning of 1996 is given by :

Sudbury (x) / Victoria (y)  = 57 /47.

As given in the question,

Let us consider population of Sudbury city be 'x'

And population of Victoria be 'y'

Given:

Population of Sudbury decreased by 6%

= x - ( 6%of x)

= x - (6x/100)

= 94x/100

Population of Sudbury increased by 14%

= y + ( 14%of y)

= y + (14y/100)

= 114y/100

Ratio of the population of the two cities in the beginning of 1996 is given by:

Population of two cities were equal

94x/100 = 114y/100

⇒ x / y = 114 /94

⇒ x / y = 57 /47

Therefore, for the given data of population of two cities Sudbury and Victoria , the ratio of the population of the two cities in the beginning of 1996 is given by :

Sudbury (x) / Victoria (y)  = 57 /47.

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