Respuesta :
The magnitude of the magnetic field at a point on the axis of the coil a distance of 6.70 cm from the center is 22.58 × 10⁻⁵ T
What is magnetic field?
A coil with current through it produces a magnetic field along its axis. This is defined by the Biot-Savart law. In the current setup, investigations of the magnetic field along the axis using coils and windings of various dimensions are investigated. The magnetic field is measured with an axial hall probe and a digital gauss meter.
For the given case:
B = (μ/4p)(2pR²×420I/x²+R²)∧³/₂
B = Magnitude of the magnetic field
P = Point on the axis of the coil (6.70 cm)
R = Radius of coil (2.5 cm)
I =Current (0.500 A)
x = Number of turns (420)
Now, substitute the values in above formula.
B = 22.58 × 10⁻⁵ T
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The complete question is as follows:
A closely wound, circular coil with a diameter of 5.00 cm has 420 turns and carries a current of 0.500 A.
What is the magnitude of the magnetic field at a point on the axis of the coil a distance of 6.70 cm from its center?
