a circular-loop tv antenna with 0.02 m2 area is in the presence of a uniform-amplitude 300 mhz signal. when oriented for maximum response, the loop develops an emf with a peak value of 30 (mv). what is the peak magnitude of b of the incident wave?

Respuesta :

The peak magnitude of the incident wave falling on the circular loop of TV antenna is 0.79 Tesla.

The area of the circular loop of the TV antenna is 0.02 it has a uniform amplitude of 300 it is oriented to give maximum response.

He developed the peak EMF of 30mV.

The maximum EMF induced in the circular coil can be given by the formula,

E = NBA2πf

Where,

N is the number of turns, B is the magnetic field, A is the area of the loop, f is the frequency and E is the EMF induced in the coil.

Now, putting the values accordingly,

30/1000 = (1)(B)(0.02)(2)(π)(300/1000)

B = 0.79 T.

The peak magnitude of the magnetic field of the incident where is 0.79 Tesla.

To know more about induced EMF, visit,

https://brainly.com/question/17329842

#SPJ4

ACCESS MORE