Respuesta :

The z-score that has a p-value of 0.2296, using the normal distribution, is of:

z = -0.74.

How to obtain probabilities using the normal distribution?

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.
  • Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.

The p-value of the z-score in this problem is given as follows:

0.2296.

Hence the z-score is found looking at the z-table for which z-score has a p-value of 0.2296, and this z-score is of:

z = -0.74.

More can be learned about the normal distribution at https://brainly.com/question/25800303

#SPJ1

ACCESS MORE