The z-score that has a p-value of 0.2296, using the normal distribution, is of:
z = -0.74.
The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The p-value of the z-score in this problem is given as follows:
0.2296.
Hence the z-score is found looking at the z-table for which z-score has a p-value of 0.2296, and this z-score is of:
z = -0.74.
More can be learned about the normal distribution at https://brainly.com/question/25800303
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