Question

benzene, c6h6, is a known carcinogen that burns in air according to the following equation: 2c6h6(l) 15o2(g) 12co2(g) 6h2o(g) (a) what is the mole ratio of o2 to c6h6? (b) how many moles of o2 are required to react with each mole of c6h6? (c) how many moles of o2 are required to react with 0.38 mol of c6h6?

Answer 1

A. The mole ratio of $O_2$ to $C_6H_6$ would be 15:2.

B. Each mole of $C_6H_6$ will require 7.5 moles of $O_2$.

C. The mole of $O_2$ that would be required to react with 0.38 mol of $C_6H_6$ will be 2.85 moles.

Stoichiometric mole ratio

From the balanced equation of the reaction when $C_6H_6$ burns in air which is written as follows:

$2C_6H_6 + 15O_2 -- > 12CO_2 + 6H_2O$

The mole ratio of $O_2$ to $C_6H_6$ is 15:2. This means eve 1 mole of $C_6H_6$ requires 7.5 moles of $O_2$ in order to burn completely.

A. The mole ratio  of $O_2$ to $C_6H_6$ is 15:2

B. Each mole of  $C_6H_6$ requires 7.5 moles of $O_2$ as follows:

    15 mols $O_2$ = 2 mol  $C_6H_6$

    1 mol $C_6H_6$ = 15 x 1/2

                         = 7.5 moles

C. With 0.38 mol of $C_6H_6$, the moles of oxygen required can be determined as follows:

1 mole  $C_6H_6$ = 7.5 moles $O_2$

0.38 mole $C_6H_6$ = 7.5 x 0.38/1

                            = 2.85 moles of $O_2$

Thus, the number of moles of $O_2$ required to react with 0.38 moles of $C_6H_6$ is 2.85 moles.

More on mole ratios can be found here: https://brainly.com/question/14425689

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