Question

a game is played with tokens according to the following rule. in each round, the player with the most tokens gives one token to each of the other players and also places one token in the discard pile. the game ends when some player runs out of tokens. players aa, bb, and cc start with 15, 14, and 13 tokens, respectively. how many rounds will there be in the game?

Answer 1

As there are three players, the game will be played in cycles of 3 rounds. After each cycle is completed, the round after will be the round where every single player has 1 token less than they did at the beginning of the previous cycle.

After the first round of the game, player one will have 12 tokens, player two will have 15 and player three will have 14 left. Looking at this sequence, it is evident that player one will finish first.

Go a few rounds to establish the pattern:

Beginning chips: A B C

15 14 13

1st round:

12 15 14

2nd round: 13 12 15

3rd round: 14 13 12

So after 3 rounds and successive 3 rounds each player has one less than he started with at the beginning of the 3 round series.

So after 36 rounds each will be down 12 from the beginning:

                                            A B C

                                             3 2 1

On the 37 round A will give up his 3 to end at 0

37

For more clear understanding:

As player has one token less at the beginning of a new cycle than he/she had at the beginning of the previous cycle we go (12∗3)+1=37(12∗3)+1=37 to see how many turns it will take them to reach zero.

Learn more about Sequence:
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