The ratio of the moles of a solute to the volume of the solution is called its molarity. The molarity of the acid solution can be calculated by dividing the quantity of HCl (in moles) by the volume (in liters) of solution in which it was dissolved.
The calculations of stoichiometry in samples and pure materials whose mass could be measured by weighing Frequently, a gas existed in the reactant.
Applying the ideal gas equation and the idea of molar volume in these situations would allow us to calculate the mass of the sample if we knew its pressure, volume, and temperature.
We can now include solutions in stoichiometric calculations by using a conversion factor that takes the concentration of a solution into account.
Example :
How much barium sulfate is precipitated when a surplus of sulfuric acid is added to 55.6 mL of 0.54 M barium chloride?
Solution
BaCl2 + H2SO4 = BaSO4 + 2 HCl
presented with 55.6 mL of 0.54 M BaCl2
Conversion variables
One mol of BaCl2 creates one mol of BaSO4, which weighs 233.4 g, and there are 0.54 mol of BaCl2 in one liter and 0.54 mmol in one milliliter of BaCl2, respectively.
Answer to the equation in math: 7.0 g BaSO4.
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