Respuesta :
Answer: 1.4 grams/cubic centimeters
Step-by-step explanation:
density = mass/volume
examples:
Step 1: Find the mass and volume of the sugar cube.
Mass = 11.2 grams
Volume = cube with 2 cm sides.
The volume of a cube = (length of a side)3
Volume = (2 cm)3
Volume = 8 cm3
Step 2: Plug your variables into the density formula.
density = mass/volume
density = 11.2 grams/8 cm3
density = 1.4 grams/cm3
Answer 1: The sugar cube has a density of 1.4 grams/cm3.
Question 2: A water and salt solution contains 25 grams of salt in 250 mL of water. What is the density of the salt water? (Use density of water = 1 g/mL)
Step 1: Find the mass and volume of the salt water.
This time, there are two masses. The mass of the salt and the mass of the water are both needed to find the mass of the salt water. The mass of the salt is given, but only the volume of water is provided. We've also been given the density of water so that we can calculate the mass of the water.
density water = mass water/volume water
solve for mass water,
mass water = densitywater·volumewater
mass water = 1 g/mL · 250 mL
mass water = 250 grams
Now we have enough to find the mass of the salt water.
mass total = mass salt + mass water
mass total = 25 g + 250 g
mass total = 275 g
The volume of the salt water is 250 mL.
Step 2: Plug your values into the density formula.
density = mass/volume
density = 275 g/250 mL
density = 1.1 g/mL
Answer 2: The salt water has a density of 1.1 gram
Answer:
1.4 g/cm³
Step-by-step explanation:
Formula for density:
[tex]\boxed{\rho=\dfrac{m}{v}}[/tex]
where:
- ρ is density.
- m is mass.
- v is volume.
Given:
- m = 770 g
- v = 550 cm³
Substitute the given values into the formula:
[tex]\implies \rho=\dfrac{770}{550}[/tex]
[tex]\implies \rho=1.4\;\sf g/cm^3[/tex]