Respuesta :

Answer: 1.4 grams/cubic centimeters

Step-by-step explanation:

density = mass/volume

examples:

Step 1: Find the mass and volume of the sugar cube.

Mass = 11.2 grams

Volume = cube with 2 cm sides.

The volume of a cube = (length of a side)3

Volume = (2 cm)3

Volume = 8 cm3

Step 2: Plug your variables into the density formula.

density = mass/volume

density = 11.2 grams/8 cm3

density = 1.4 grams/cm3

Answer 1: The sugar cube has a density of 1.4 grams/cm3.

Question 2: A water and salt solution contains 25 grams of salt in 250 mL of water. What is the density of the salt water? (Use density of water = 1 g/mL)

Step 1: Find the mass and volume of the salt water.

This time, there are two masses. The mass of the salt and the mass of the water are both needed to find the mass of the salt water. The mass of the salt is given, but only the volume of water is provided. We've also been given the density of water so that we can calculate the mass of the water.

density water = mass water/volume water

solve for mass water,

mass water = densitywater·volumewater

mass water = 1 g/mL · 250 mL

mass water = 250 grams

Now we have enough to find the mass of the salt water.

mass total = mass salt + mass water

mass total = 25 g + 250 g

mass total = 275 g

The volume of the salt water is 250 mL.

Step 2: Plug your values into the density formula.

density = mass/volume

density = 275 g/250 mL

density = 1.1 g/mL

Answer 2: The salt water has a density of 1.1 gram

Answer:

1.4 g/cm³

Step-by-step explanation:

Formula for density:

[tex]\boxed{\rho=\dfrac{m}{v}}[/tex]

where:

  • ρ is density.
  • m is mass.
  • v is volume.

Given:

  • m = 770 g
  • v = 550 cm³

Substitute the given values into the formula:

[tex]\implies \rho=\dfrac{770}{550}[/tex]

[tex]\implies \rho=1.4\;\sf g/cm^3[/tex]

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