A race car traveling at 44 meters per second on a racetrack and reducing its speed steadily over the course of 11 seconds to 22 meters per second would have covered 363 meters.
Newton provided three equations of motion.
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
Remember that these equations only allow for uniform acceleration.
as stated in the issue We must determine the distance traveled by a race car if it moves along a racetrack at 44 meters per second and gradually slows down to 22 meters per second over the course of 11 seconds.
Using the initial motion equation,
v = u + at
22 = 44 + 11a
a = 22-44/11
a = -2 m/s²
The third equation of motion is used in the,
v² - u² = 2×a×s
22² - 44² = 2×(-2)s
s = 363 meters
The race car would have covered 363 meters.
To know more about equations of motion visit:
https://brainly.com/question/11744179
#SPJ4
