Question

suppose you mix 100.0 g of water at 23.1 oc with 75.0 g of water at 73.1 oc. what will be the final temperature of the mixed water, in oc?

Answer 1

The final temperature of the mixed water is 45.6 ⁰C.

How to estimate final temperature?

The calorimeter's final temperature is 59.0 °C. We can use our calorimeter to measure the quantity of heat a reaction releases now that we are aware of its heat capacity.

The given parameters;

mass of the cold water, m = 100 g

initial temperature of the water, t₁ = 23 ⁰C

initial  temperature of the hot water, t₂ = 75.7⁰ C

mass of the hot water = 75 g

specific heat capacity of water is 4.184 J/g⁰C

The final temperature of the mixture is calculated as follows;

Based on the principle of conservation of energy;

Heat lost by hot water = heat gained by the cold water

mcΔθ₂ = mcΔθ₁

75 x 4.184 x (75.7 - T) = 100 x 4.184 x (T - 23)

75 x (75.7 - T) = 100 x (T - 23)

(75.7 - T) = 1.333(T - 23)

75.7 - T = 1.333T - 30.659

75.7 + 30.659 = 1.333T + T

106.359  = 2.333T

T = 106.359/2.333

T= 45.6° C

Therefore The final temperature of the mixed water is 45.6 ⁰C.

To learn more about final temperature refer to:

https://brainly.com/question/22338034

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