In, 11 years Mark will be twice as old as his son Brian. Mark will be 44 while his son Brian will be 22 in 11 years time.
Mark is three times as old as his son Brian. In ten years, mark will be 43 years old. The number of years Mark will be twice as old as Brian can be calculated as follows:
let
Brian age = x
Mark's age = 3x
In ten years, Mark will be 43 years old.
Hence,
3x + 10 = 43
Subtract 10 from both sides of the equation
3x + 10 = 43
3x + 10 - 10 = 43 - 10
3x = 33
divide both side of the equation by 3
x = 33 / 3
x = 11
Therefore, the age of Mark is 33 years and the age of his son is 11 years.
Therefore,
2x = Age of Brian
Therefore, in 11 years Mark will be twice as old as his son.
His son will be 22 while Mark will be 44 years.
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