Respuesta :
232 ml of water should be added assuming the volumes as additives calculated by the dilution factor.
Dilutions is that the ratio that exists between the concentration of the concentrated solution and that of the diluted solution is equal to the ratio that exists between the volume of the diluted solution and that of the concentrated solution. This ratio is called the dilution factor.
we have,
DF = concentration of the concentrated solution/ concentration of the diluted solution
and
DF = volume of the diluted solution/volume of the concentrated solution
The solution must be diluted from an initial concentration of 0.600 M to a final concentration of 0.100 M, the equivalent of a dilution factor equal to
DF=0.600M/0.100M=6
You can now say that the volume of the diluted solution must be 6
times greater than the volume of the concentrated solution, since
DF=volume of diluted solution 47.0 mL
volume of diluted solution = DF×47.0 mL
and therefore
volume of diluted solution=6 × 47.0 mL= 282 mL
Assuming that the volumes are addictive, you will have to add
volume of water added = 282 mL− 47.0 mL= 235 mL
of water to your concentrated solution in order to go from
47.0 mL of 0.600 M solution to 235 mL of 0.100 M solution.
To learn more about Dilution Factor please visit:
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