The molarity of the naocl(aq) solution when Reaction 2 occurs when an excess of 6 m hcl(aq) solution is added to 100. Ml of naocl(aq) of unknown concentration. If the reaction goes to completion and 0 is The molarity of the NaOCl answer is 0.10 M.
- We'll start with the aid of using calculating the quantity of mole of NaOCI required to supply 0.010 mole of Cl This may be received as follow:
- NaOCl + 2HCl -> Cl + NaCl + H2O
- From the balanced equation above,
- 1 mole of NaOCI reacted to supply 1 mole FCL
- Therefore 0.010 mole of NaOCI may also react to supply 0.010 mole of CL .
- Finally, we will decide the molarity of the NaOCl answer.
- Mole of NaOCI = 0.01 mole
- Volume = 100mL = 100/1000 = 0.1L.
- Molarity of NaOCI =?
- Molarity = mole / Volume
- Molarity of NaOCI = 0.01/0.1
- Molarity of NaOCl = 0.10 M
- Therefore, the molarity of the NaOCI answer is 0.10 M
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