the length of time it takes college students to find a parking spot in the library parking lot follows a normal distribution with a mean of 5.5 minutes and a standard deviation of 1 minute. find the probability that a randomly selected college student will find a parking spot in the library parking lot in less than 5.0 minutes.

Respuesta :

The probability that a randomly selected college student will find a parking spot in the library parking lot in less than 5.0 minutes, using the normal distribution, is of:

0.3085 = 30.85%.

How to obtain probabilities using the normal distribution?

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.
  • Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.

The mean and the standard deviation for the times are given as follows:

[tex]\mu = 5.5, \sigma = 1[/tex]

The probability of taking less than 5 minutes is the p-value of Z when X = 5, hence:

Z = (5 - 5.5)/1

Z = -0.5.

Z = -0.5 has a p-value of 0.3085.

Hence the probability is of:

0.3085 = 30.85%.

More can be learned about the normal distribution at https://brainly.com/question/25800303

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