Question

if the mass of the box is 12 kg, theta is 30 degrees and the force f is 25 n, what is the normal force?

Answer 1

The normal force that acts on the box is 102 N.

What is the normal force?

We know that according to the Newton's third law, action and reaction are equal and opposite. The implication of this is that, if a force acts on a surface, then the surface would exert back the same magnitude of force on the body that first exerted the force only that the force would now be in the opposite direction.

We can tell that the force that is acting on the box is a foward force of about 25N. This is the force that is trying to move the box in the forward direction against the forces of friction. We are now asked for the normal force that acts on the box.

Normal force = mg cosθ

m = mass of the body

g = acceleration due to gravity

θ  angle of inclination

Normal force = 12 Kg * 9.8 m/s^2 * cos 30

= 102 N

The normal force is therefore 102N.

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