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the electron in a ground-state h atom absorbs a photon of wavelength 102.57 nm. to what energy level does the electron move?

Respuesta :

The energy level of electronic transition can be predicted using Rydberg formula. Using this formula the energy level of electron will be n = 3 after the  absorption of a photon of wavelength 101.57.

What is electronic transitions?

Electrons from lower energy level transits to higher energy levels by absorbing energy. But they are not stable in the excited state and thus return to the ground state by emitting the absorbed energy.

Let n1 be the ground state and n2 be the excited state and the Rydberg constant is 1.097 × 10⁷ m⁻¹. Then the Rydberg formula for a wavelength lambda is written as:

[tex]\frac{1}{\lambda} = 1.09 \times 10 ^{7} [\frac{1}{n1^{2}} -\frac{1}{n2^{2}}][/tex]

Apply these values for the ground state of hydrogen atom that is n1 =1,

1/(102.57 × 10⁻⁹ m) = 1.097 × 10⁷ m⁻¹ [1 - 1/n2²]

  n2² = 9

   n2 = 3.

Therefore, the electron will move on n= 3 level of energy.

To find more on electronic transition, refer here:

https://brainly.com/question/18156550

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