Question

1. a 50. ml sample of .250 m iron (iii) chloride (fecl3) is reacted with 50. ml of .250 m sodium carbonate (na2co3) solution. a. how much excess reactant is left over?

Answer 1

The amount of the excess reactants left over is 0.0042 moles.

What is the excess reactant?

We know that the term excess reactant has to do with the reactant that have been left over in the system. Now we know that the reactant that is in short supply is called the limiting reactant and that is the reactant that would determine the amount of the products that we have in the system.

Given that;

Number of moles = Concentration * volume

For the iron (iii) chloride = 0.250 M * 50/1000 L

= 0.0125 moles

For the sodium carbonate= 0.250 M * 50/1000 L

= 0.0125 moles

Thee equation of the reaction is;$2FeCl_{3} + 3Na_{2} CO_{3} ---- > Fe_{2} ( CO_{3} )_{3} + 6NaCl$

2 moles of iron (iii) chloride reacts with 3 moles of  sodium carbonate

x moles  of iron (iii) chloride reacts with  0.0125 moles

x = 0.00833 moles

Amount of excess reactant left over = 0.0125 moles - 0.00833 moles

= 0.0042 moles

Learn more about excess reactants:https://brainly.com/question/22102486

#SPJ1