Question

how many grams of water (18.016 g/mol) are theoretically produced for the following reaction given we have 2.6 moles of hcl and 1.4 moles of ca(oh)2?

Answer 1

The total grams is 46.8g which is option C. The correct answer;

2HCl  + Ca(OH)2  -------------> CaCl2   + 2H2O

2 moles HCl reacts with 1 mole Ca(OH)2

2.6 moles of HCl  reacts with  2.6 x 1 / 2 = 1.3

but we have 1.4 moles Ca(OH)2  

so Ca(OH)2 is exess reagent

HCl is limiting reagent.

2 mole HCl gives 2 moles of H2O

2.6 moles of HCl   gives 2.6 moles of H2O

convert moles to mass

moles  = mass / molar mass

mass  = moles x molar mass

mass = 2.6 x 18 = 46.8 g

answer = option c = 46.8 g

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