The value of k associated to the cubic equation f(x) = x³ + k · x + 5 is equal to - 6.
What is the value of k of a cubic equation?
In this question we have a cubic equation of the form f(x) = x³ + k · x + 5 and we need to determine the value of k such that the binomial x + 1 is a factor of f(x). A value of x is a factor of the polynomial if and only if the following expression is observed:
f(x) = 0, for x = a
If we know that x = 1 and f(1) = 0, then the value of k is:
1³ + k · 1 + 5 = 0
k + 6 = 0
k = - 6
The cubic equation has a value of k equal to - 6.
To learn more on cubic equations: https://brainly.com/question/20278509
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