The force of gravity is an attractive force that acts between any two bodies on the earth.
Given that;
F = Kq1q2/r^2
F = 90 N
r = 1 m
q1= q2 = q1^2
q1 =√Fr^2/K
q1 = √90 × 1/9.0 × 10^9
q1 = 1 × 10^-4 C
Then;
F = 9.0 × 10^9 × (1 × 10^-4 )^2/3^2
F = 10 N
2) From;
F = Gm1m2/r^2
F = 6.6 × 10^-11 Nm^2Kg^-2 × 0.156 Kg × 0.170 Kg/(0.75 m)^2
F = 3.15 x 10-12 N
3) The acceleration of a particle due to the Coulomb force depends on both the charge and the mass.
4) F = Gm1m2/r^2
Where m1=m2 = m1^2
m1 =√F/r^2/G
m1 = √20 N ( 4 m)^2/6.6 × 10^-11 Nm^2Kg^-2
m1 = 2.2 × 10^6 Kg
To find r when F = 5N
r =√Gm1^2/F
r =√6.6 × 10^-11 Nm^2Kg^-2 × (2.2 × 10^6 Kg)^2/5N
r = 8 m
Therefore the distance is 8 m
The complete question is : Two charges q1 and q2 exert a 90 N electrostatic force onto each other when they are 1 m apart. They are moved further away to a distance of 3 m. What will the new electrostatic force be?
30 N
810 N
10 N
270 N
What is the gravitational force between two billiard balls of mass 156 g and 170 g that are 75 cm apart?
-2.36 x 10-12 N
2.36 x 10-12 N
3.15 x 10-12 N
-3.15 x 10-12 N
Based on Coulomb's law, which quantities does the acceleration of a charged particle due to the Coulomb force depend on?
The acceleration depends on the charge but not on the mass.
The acceleration does not depend on the charge nor on the mass.
The acceleration depends on the mass but not on the charge.
The acceleration depends on both the charge and the mass.
Two masses m1 and m2 exert a gravitational force of 20 N onto each other when they are 4 m apart.
At what distance should they be to exert a force of 5 N onto each other?
64 m
16 m
8 m
1 m
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